February | 2017 | Spin Foam

Note: This post is just some notes for a discussion.

We can start by writing it simply as

$\displaystyle f(\mathbf{r}) = \frac{e^{ikr}}{r}$ .

Now we use $\mathbf{r} = [x\,y\,z]^T$ and assume $|z| \gg |x|, |y|$ . After expanding the expression using the coordinates,

$\displaystyle f(x, y, z) = \frac{\exp(ik\sqrt{z^2 + x^2 + y^2})}{\sqrt{z^2 + x^2 + y^2}}$ ,

we have to find now a way to get rid of the square roots. Taking $z^2$ as a common factor,

$\displaystyle \sqrt{z^2 + x^2 + y^2} = \sqrt{z^2\left(1 + \frac{x^2 + y^2}{z^2}\right)}$
$\displaystyle = |z|\sqrt{1 + \frac{x^2 + y^2}{z^2}}$ .

As we know the argument of the square root is very close to 1, we can use a first order approximation, $\sqrt{1 + x} \approx 1 + \frac{x}{2}$ :

$\approx |z|\left(1 + \frac{x^2 + y^2}{2z^2}\right)$

$\approx |z| + \frac{x^2 + y^2}{2|z|}$ .

Replacing in the original expression,

$\displaystyle f(x, y, z) \approx \frac{1}{|z|}\exp\left(ik|z| + ik\frac{x^2+y^2}{2|z|}\right)$

we get expressions matching the ones in the slides apart from some amplitude and phase conventions.

Spin Foam